Intermolecular Forces
Question 1:
Which intermolecular force is present between all molecules and atoms, and is the only IMF for nonpolar species?
- (A) Hydrogen bonding
- (B) Dipole–dipole interaction
- (C) London dispersion forces
- (D) Ion–dipole interaction
View Answer
Correct Answer: (C) London dispersion forces
Explanation: LDF arise from instantaneous/induced dipoles and act between all particles; they dominate in nonpolar substances.
Question 2:
Which substance has stronger London dispersion forces at the same temperature?
- (A) F2(g)
- (B) I2(s)
- (C) Ne(g)
- (D) CH4(g)
View Answer
Correct Answer: (B) I2(s)
Explanation: Larger electron clouds and higher polarizability increase LDF; iodine is the largest/polarizable among the choices.
Question 3:
Which molecule can form hydrogen bonds between its molecules?
- (A) CH3F
- (B) CH3NH2
- (C) H2S
- (D) CCl4
View Answer
Correct Answer: (B) CH3NH2
Explanation: Hydrogen bonding requires H directly bonded to N, O, or F; methylamine has N–H bonds.
Question 4:
Which pure substance is expected to have the lowest vapor pressure at the same temperature?
- (A) CO2(s)
- (B) H2O(l)
- (C) CCl4(l)
- (D) He(g)
View Answer
Correct Answer: (B) H2O(l)
Explanation: Strong IMFs (hydrogen bonding) lower vapor pressure.
Question 5:
Which statement best compares LDF strength across the halogens at the same temperature?
- (A) F2 > Cl2 > Br2 > I2
- (B) I2 > Br2 > Cl2 > F2
- (C) All identical due to similar valence electrons
- (D) Cl2 > I2 > Br2 > F2
View Answer
Correct Answer: (B)
Explanation: LDF increase with electron count/polarizability: F2 < Cl2 < Br2 < I2.
Question 6:
What is the primary attractive force when O2(g) dissolves in water?
- (A) Dipole–dipole
- (B) Ion–dipole
- (C) Dipole–induced dipole
- (D) Hydrogen bonding with O2
View Answer
Correct Answer: (C) Dipole–induced dipole
Explanation: Polar H2O induces a dipole in nonpolar O2, leading to attraction.
Question 7:
As intermolecular forces strengthen for a liquid at fixed temperature, which property decreases?
- (A) Boiling point
- (B) Viscosity
- (C) Vapor pressure
- (D) Surface tension
View Answer
Correct Answer: (C) Vapor pressure
Explanation: Stronger IMFs retain molecules in the liquid, lowering vapor pressure (and volatility).
Question 8:
Which pair correctly ranks expected boiling points (highest to lowest) based on dominant IMFs?
- (A) H2O > CH3OH > CH3Cl > He
- (B) He > CH3Cl > CH3OH > H2O
- (C) CH3Cl > H2O > CH3OH > He
- (D) CH3OH > H2O > CH3Cl > He
View Answer
Correct Answer: (A)
Explanation: Strong H-bond network in water > alcohol H-bonding > polar dipole–dipole > LDF only.
Question 9:
A gas mixture at 1.00 atm contains 35.0% He by moles. What is the partial pressure of He?
- (A) 0.150 atm
- (B) 0.250 atm
- (C) 0.350 atm
- (D) 0.650 atm
View Answer
Correct Answer: (C) 0.350 atm
Explanation: Dalton’s Law: pHe = XHe · Ptotal = 0.350 × 1.00 atm = 0.350 atm.
Question 10:
A rigid container holds 2.0 mol N2 and 1.0 mol O2 at the same T. What is the ratio p(N2):p(O2)?
- (A) 1:1
- (B) 1:2
- (C) 2:1
- (D) 3:1
View Answer
Correct Answer: (C) 2:1
Explanation: For ideal gases in the same V and T, p ∝ n. So p(N2):p(O2) = 2.0:1.0.
Question 11:
Which is not an assumption of the Kinetic Molecular Theory for ideal gases?
- (A) Particles are in constant random motion.
- (B) Collisions are perfectly elastic.
- (C) Particles exert attractive and repulsive forces on each other.
- (D) Particle volume is negligible compared to container volume.
View Answer
Correct Answer: (C)
Explanation: Ideal gases are assumed to have no IMFs; (A), (B), and (D) are KMT assumptions.
Question 12:
At the same temperature, which statement is true for different ideal gases?
- (A) All have the same average speed.
- (B) All have the same average kinetic energy.
- (C) Heavier gases have higher rms speeds.
- (D) Lighter gases have lower most probable speeds.
View Answer
Correct Answer: (B)
Explanation: ⟨KE⟩ depends only on T; speeds depend on molar mass (lighter → faster).
Question 13:
Which gas has the highest rms speed at 298 K?
- (A) He
- (B) N2
- (C) Ar
- (D) SF6
View Answer
Correct Answer: (A) He
Explanation: vrms ∝ √(T/M); the smallest molar mass (He) moves fastest at the same T.
Question 14:
Under which conditions does a real gas behave most ideally?
- (A) Low T, high P
- (B) High T, low P
- (C) Low T, low P
- (D) High T, high P
View Answer
Correct Answer: (B) High T, low P
Explanation: High T reduces IMF effects; low P makes particle volume negligible.
Question 15:
Which combination most increases deviations from ideal behavior?
- (A) Low T and high P
- (B) High T and low P
- (C) Very low molar mass
- (D) Large container volume
View Answer
Correct Answer: (A) Low T and high P
Explanation: Low T → IMFs matter; high P → finite particle volume matters.
Question 16:
How does the Maxwell–Boltzmann speed distribution change when temperature increases for a given gas?
- (A) Peak shifts to lower speed and narrows
- (B) Peak shifts to higher speed and broadens
- (C) Peak height and position remain unchanged
- (D) Distribution becomes symmetric about the mean
View Answer
Correct Answer: (B)
Explanation: Higher T → higher average/most probable speeds and a broader distribution.
Question 17:
According to Graham’s law, how many times faster does H2 effuse than O2 at the same T?
- (A) 2
- (B) 3
- (C) 4
- (D) 8
View Answer
Correct Answer: (C) 4
Explanation: Rate ∝ 1/√M; √(MO2/MH2) = √(32/2) = √16 = 4.
Question 18:
For a real gas at moderate high pressure, the measured pressure is often lower than ideal. The best explanation is:
- (A) Particle volume increases collision frequency
- (B) Attractive forces reduce momentum transfer on the walls
- (C) Collisions are inelastic
- (D) Temperature spontaneously decreases
View Answer
Correct Answer: (B)
Explanation: Intermolecular attractions pull particles inward, decreasing effective wall impacts.
Question 19:
At the same T and P, which ideal gas sample has the greatest density?
- (A) He
- (B) N2
- (C) O2
- (D) SF6
View Answer
Correct Answer: (D) SF6
Explanation: For ideal gases, ρ = PM/RT; at fixed P and T, density ∝ molar mass.
Question 20:
A sealed rigid container of an ideal gas is cooled from 350 K to 250 K. Which changes correctly describe the system?
- (A) Pressure increases; average KE increases; most probable speed increases
- (B) Pressure decreases; average KE decreases; most probable speed decreases
- (C) Pressure unchanged; average KE unchanged; speed unchanged
- (D) Pressure decreases; average KE unchanged; speed decreases
View Answer
Correct Answer: (B)
Explanation: In a rigid container, P ∝ T; kinetic energy and characteristic speeds scale with T.
Question 21:
Which substance exhibits dipole–dipole interactions (as a significant IMF) between its molecules?
- (A) CH2Cl2
- (B) CO2
- (C) CCl4
- (D) Xe
View Answer
Correct Answer: (A) CH2Cl2
Explanation: Dichloromethane is polar and shows dipole–dipole forces; the others are nonpolar and rely on LDF only.
Question 22:
Which order correctly ranks boiling points (highest to lowest) for the noble gases?
- (A) He > Ne > Ar > Kr > Xe
- (B) Xe > Kr > Ar > Ne > He
- (C) Ne > He > Ar > Kr > Xe
- (D) Ar > Xe > Kr > Ne > He
View Answer
Correct Answer: (B)
Explanation: Boiling point increases with molar mass/polarizability, strengthening LDF.
Question 23:
An ideal gas (n = 0.500 mol) in a 10.0 L rigid container at 300 K has what pressure (R = 0.0821 L·atm·mol−1·K−1)?
- (A) 0.82 atm
- (B) 1.23 atm
- (C) 1.50 atm
- (D) 2.46 atm
View Answer
Correct Answer: (B) 1.23 atm
Explanation: P = nRT/V = (0.500)(0.0821)(300)/10.0 ≈ 1.23 atm.
Question 24:
Hydrogen is collected over water at 25 °C. If the total pressure is 760 torr and the water vapor pressure is 24 torr, what is the partial pressure of H2?
- (A) 724 torr
- (B) 736 torr
- (C) 760 torr
- (D) 784 torr
View Answer
Correct Answer: (B) 736 torr
Explanation: p(H2) = Ptot − p(H2O) = 760 − 24 = 736 torr.
Question 25:
At the same temperature, how many times faster does NH3 effuse than CO2?
- (A) 1.2×
- (B) 1.6×
- (C) 2.0×
- (D) 2.6×
View Answer
Correct Answer: (B) 1.6×
Explanation: Rate ∝ 1/√M; √(44/17) ≈ 1.61.
Question 26:
The compressibility factor Z = PV/(nRT) for a real gas at moderate pressure is often < 1. What is the best reason?
- (A) Particle volume dominates
- (B) Attractive forces lower the measured pressure
- (C) Inelastic collisions reduce temperature
- (D) R is not constant for real gases
View Answer
Correct Answer: (B)
Explanation: Attractions pull molecules inward, reducing wall impacts → P real < P ideal → Z < 1.
Question 27:
At the same T and P, which gas is expected to deviate most from ideal behavior?
- (A) He
- (B) CH4
- (C) CO2
- (D) NH3
View Answer
Correct Answer: (D) NH3
Explanation: Stronger IMFs (H-bonding capability) cause greater non-ideality than weakly interacting gases.
Question 28:
For gases at the same temperature, which statement about the Maxwell–Boltzmann distribution is correct?
- (A) He has a narrower distribution than Ar
- (B) He and Ar have identical distributions
- (C) He has a broader distribution shifted to higher speeds
- (D) Ar peaks at higher speed than He
View Answer
Correct Answer: (C)
Explanation: Lighter gases move faster on average and show broader speed distributions at the same T.
Question 29:
Which pair is best described by a dipole–induced dipole attraction?
- (A) HCl (polar) and Ar (nonpolar)
- (B) CO2 and CH4
- (C) H2O and H2O
- (D) Cl2 and Cl2
View Answer
Correct Answer: (A)
Explanation: A polar molecule (HCl) can induce a dipole in a nonpolar atom (Ar). (C) is H-bonding; (B,D) are LDF only.
Question 30:
What is the density of O2(g) at STP (1 atm, 273 K)?
- (A) 0.89 g·L−1
- (B) 1.00 g·L−1
- (C) 1.43 g·L−1
- (D) 2.86 g·L−1
View Answer
Correct Answer: (C) 1.43 g·L−1
Explanation: ρ = PM/RT = (1)(32)/(0.0821×273) ≈ 1.43 g·L−1.
Question 31:
A gas has density 1.25 g·L−1 at STP. What is its molar mass?
- (A) 16 g·mol−1
- (B) 28 g·mol−1
- (C) 32 g·mol−1
- (D) 44 g·mol−1
View Answer
Correct Answer: (B) 28 g·mol−1
Explanation: M = ρRT/P = 1.25×(0.0821×273)/1 ≈ 28 g·mol−1.
Question 32:
In a gas mixture, XA = 0.60 and the total pressure is 1.50 atm. What is pA?
- (A) 0.60 atm
- (B) 0.75 atm
- (C) 0.90 atm
- (D) 1.50 atm
View Answer
Correct Answer: (C) 0.90 atm
Explanation: pA = XA×Ptot = 0.60×1.50 = 0.90 atm.
Question 33:
At very high pressures, many real gases show Z > 1 mainly because:
- (A) Attractions dominate and lower P
- (B) Repulsions/finite particle volume dominate
- (C) Temperature becomes non-constant
- (D) R increases with pressure
View Answer
Correct Answer: (B)
Explanation: Excluded volume (repulsions) makes the gas less compressible than ideal → Z > 1.
Question 34:
Which ranking (strongest to weakest) of typical IMFs is generally correct for small molecules?
- (A) LDF > H-bond > dipole–dipole
- (B) H-bond > dipole–dipole > LDF
- (C) Dipole–dipole > H-bond > LDF
- (D) LDF = dipole–dipole = H-bond
View Answer
Correct Answer: (B)
Explanation: Hydrogen bonding is strongest, then dipole–dipole, then LDF (on a per-molecule basis).
Question 35:
Which has the higher boiling point at 1 atm, mainly due to greater surface area (stronger LDF)?
- (A) Neopentane (2,2-dimethylpropane)
- (B) n-Pentane
- (C) Both the same
- (D) Cannot be predicted
View Answer
Correct Answer: (B) n-Pentane
Explanation: Less compact isomers have greater contact area → stronger LDF → higher b.p.
Question 36:
At 298 K, which correctly orders most probable molecular speeds (highest to lowest)?
- (A) Ar > Ne > He
- (B) He > Ne > Ar
- (C) Ne > He > Ar
- (D) All equal at same T
View Answer
Correct Answer: (B) He > Ne > Ar
Explanation: Speeds scale as 1/√M; lighter gases move faster at the same temperature.
Question 37:
For an ideal gas at constant pressure, if the temperature (K) is doubled, the volume will:
- (A) Halve
- (B) Remain the same
- (C) Double
- (D) Quadruple
View Answer
Correct Answer: (C) Double
Explanation: Charles’s law: V ∝ T at constant P and n.
Question 38:
For an ideal gas at constant temperature, compressing the volume to one-half will cause the pressure to:
- (A) Halve
- (B) Stay constant
- (C) Double
- (D) Quadruple
View Answer
Correct Answer: (C) Double
Explanation: Boyle’s law: P ∝ 1/V at constant T and n.
Question 39:
Which pair experiences only London dispersion forces between molecules?
- (A) N2 and CH4
- (B) HCl and H2O
- (C) NH3 and HF
- (D) CH3Cl and CH3CH2OH
View Answer
Correct Answer: (A)
Explanation: N2 and CH4 are nonpolar; interactions are LDF. The others have permanent dipoles and/or H-bonding.
Question 40:
Oxygen is collected over water at 25 °C. If the total pressure is 755 torr and p(H2O) = 24 torr, what is p(O2)?
- (A) 731 torr
- (B) 751 torr
- (C) 755 torr
- (D) 779 torr
View Answer
Correct Answer: (A) 731 torr
Explanation: Dalton’s law: p(O2) = 755 − 24 = 731 torr.
Question 41:
At 25 °C, which liquid has the higher vapor pressure?
- (A) Hexane (C6H14)
- (B) Octane (C8H18)
- (C) They are the same
- (D) Cannot be determined
View Answer
Explanation: Weaker IMFs → higher vapor pressure. Hexane has fewer electrons and weaker LDF than octane.
Correct Answer: (A) Hexane
Question 42:
Which pure substance shows hydrogen bonding between identical molecules?
- (A) CH3F
- (B) HF
- (C) H2S
- (D) CH3OCH3 (dimethyl ether)
View Answer
Explanation: Hydrogen bonding requires H directly bonded to N, O, or F. Only HF meets this in the pure substance.
Correct Answer: (B) HF
Question 43:
Which liquid is expected to have the highest viscosity at room temperature?
- (A) Hexane
- (B) Water
- (C) Ethanol
- (D) Glycerol (C3H8O3)
View Answer
Explanation: Glycerol can form multiple hydrogen bonds per molecule, greatly increasing viscosity.
Correct Answer: (D) Glycerol
Question 44:
Capillary rise is greatest for which pair?
- (A) Water in glass
- (B) Mercury in glass
- (C) Hexane in PTFE (Teflon)
- (D) Bromine in glass
View Answer
Explanation: Strong adhesive forces between water and glass plus H-bonding → strong capillarity. Mercury shows depression (concave-down meniscus).
Correct Answer: (A) Water in glass
Question 45:
Which gas has the highest root-mean-square (rms) speed at 298 K?
- (A) H2
- (B) He
- (C) N2
- (D) O2
View Answer
Explanation: \(u_{\text{rms}}\propto \sqrt{T/M}\). The smallest molar mass (H2) gives the highest speed at the same T.
Correct Answer: (A) H2
Question 46:
Approximate the rms speed of N2(g) at 300 K. (Use \(u_{\text{rms}}=\sqrt{3RT/M}\), R = 8.314 J·mol−1·K−1, M = 0.028 kg·mol−1)
- (A) 290 m·s−1
- (B) 400 m·s−1
- (C) 517 m·s−1
- (D) 870 m·s−1
View Answer
Calculation: \(\sqrt{(3)(8.314)(300)/0.028}\approx 5.17\times10^{2}\) m·s−1.
Correct Answer: (C) 517 m·s−1
Question 47:
A mixture has 2.0 mol N2 and 1.0 mol O2. If total pressure is 900 torr, what is the partial pressure of N2?
- (A) 300 torr
- (B) 450 torr
- (C) 600 torr
- (D) 900 torr
View Answer
Calculation: \(\chi_{\text{N2}}=2/3\); \(P_{\text{N2}}=\chi P_{\text{tot}}=(2/3)(900)=600\) torr.
Correct Answer: (C) 600 torr
Question 48:
A 2.00 L rigid flask at 27 °C contains 0.080 mol of an ideal gas. What is the pressure?
- (A) 0.49 atm
- (B) 0.74 atm
- (C) 0.98 atm
- (D) 1.6 atm
View Answer
Calculation: \(P=\dfrac{nRT}{V}=\dfrac{(0.080)(0.0821)(300)}{2.00}\approx0.985\) atm.
Correct Answer: (C) 0.98 atm
Question 49:
A gas at 0.80 atm, 3.00 L, and 300 K is compressed to 1.50 L and cooled to 200 K. What is the new pressure?
- (A) 0.53 atm
- (B) 0.80 atm
- (C) 1.07 atm
- (D) 1.60 atm
View Answer
Calculation: \(P_2=P_1\frac{V_1}{V_2}\frac{T_2}{T_1}=0.80\cdot\frac{3.00}{1.50}\cdot\frac{200}{300}\approx1.07\) atm.
Correct Answer: (C) 1.07 atm
Question 50:
Under which conditions do real gases behave most ideally?
- (A) Low T, high P, strong IMFs
- (B) Low T, low P, strong IMFs
- (C) High T, low P, weak IMFs, small molar mass
- (D) High T, high P, strong IMFs
View Answer
Explanation: High T minimizes attractions; low P makes particle volume negligible; weak IMFs and small M also help.
Correct Answer: (C)
Question 51:
Which halogen molecule has the strongest London dispersion forces?
- (A) F2
- (B) Cl2
- (C) Br2
- (D) I2
View Answer
Explanation: LDF increase with electron count/polarizability. I2 is largest.
Correct Answer: (D) I2
Question 52:
Which compound has the highest normal boiling point?
- (A) CH4
- (B) CH3CHO (acetaldehyde)
- (C) CH3OCH3 (dimethyl ether)
- (D) CH3CH2OH (ethanol)
View Answer
Explanation: Ethanol can donate and accept H-bonds; the others cannot donate H-bonds.
Correct Answer: (D) Ethanol
Question 53:
When temperature increases for a gas, the Maxwell–Boltzmann speed distribution:
- (A) Peaks higher and narrows
- (B) Shifts to higher speeds and broadens
- (C) Shifts to lower speeds and broadens
- (D) Does not change
View Answer
Explanation: Higher T → higher average speed, broader distribution, lower peak height.
Correct Answer: (B)
Question 54:
Graham’s law: What is the effusion rate ratio \(r_{\text{He}}/r_{\text{O2}}\) at the same T and P?
- (A) 0.35
- (B) 1.9
- (C) 2.8
- (D) 4.0
View Answer
Calculation: \(r\propto 1/\sqrt{M}\) so \(r_{\text{He}}/r_{\text{O2}}=\sqrt{32/4}=\sqrt{8}\approx2.8\).
Correct Answer: (C) 2.8
Question 55:
In the van der Waals equation, which parameter primarily corrects for intermolecular attractions?
- (A) a
- (B) b
- (C) R
- (D) T
View Answer
Explanation: The constant a reduces effective pressure due to attractions; b corrects for finite molecular volume.
Correct Answer: (A) a
Question 56:
Two different ideal gases are in the same container at the same temperature. Which statement is true?
- (A) The lighter gas has greater average kinetic energy
- (B) Both gases have the same average kinetic energy
- (C) The heavier gas has greater average kinetic energy
- (D) Average kinetic energy depends on molar mass, not temperature
View Answer
Explanation: \(\overline{KE}=\tfrac{3}{2}RT\); depends only on T for ideal gases.
Correct Answer: (B)
Question 57:
At 25 °C, which has the higher vapor pressure?
- (A) Water
- (B) Acetone ((CH3)2CO)
- (C) They are equal
- (D) Not enough information
View Answer
Explanation: Acetone cannot donate H-bonds between its own molecules; weaker IMFs → higher vapor pressure than water.
Correct Answer: (B) Acetone
Question 58:
Which sample contains the greatest number of gas molecules?
- (A) 2.0 L at 1.0 atm and 300 K
- (B) 1.0 L at 2.0 atm and 300 K
- (C) 3.0 L at 0.80 atm and 400 K
- (D) 1.5 L at 1.2 atm and 350 K
View Answer
Calculation: \(n=\dfrac{PV}{RT}\). A: \(2.0/300\); B: \(2.0/300\) (tie); C: \(2.4/400\) (smaller); D: \(1.8/350\) (smaller).
Correct Answer: (A) and (B) (tie)
Question 59:
Which gas has the greater average speed at the same temperature?
- (A) SO2
- (B) CO
- (C) CO2
- (D) H2S
View Answer
Explanation: At the same T, lighter gases move faster on average. CO (M ≈ 28) is lighter than SO2, CO2, and H2S.
Correct Answer: (B) CO
Question 60:
Which statement about volatility, vapor pressure, and IMFs is correct at a fixed temperature?
- (A) Stronger IMFs → higher vapor pressure → higher boiling point
- (B) Weaker IMFs → higher vapor pressure → lower boiling point
- (C) Stronger IMFs → higher vapor pressure → lower boiling point
- (D) Vapor pressure is independent of IMFs
View Answer
Explanation: Weak IMFs make molecules escape more easily, increasing vapor pressure and lowering the boiling point.
Correct Answer: (B)
8, 18, 24, 37
49
44번 ,40 , 41번 넣어야함 , 39번, 38 -> n2o4 로 바꾸기.